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Tap for more steps... y = 0.625 y = 0.625. The cubic function can be graphed using the function behavior and the points. x y −2 −5 −1 −0.625 0 0 1 0.625 2 5 x y - 2 - 5 - 1 - 0.625 0 0 1 0.625 2 5. The cubic function can be graphed using the function behavior and the selected points. Falls to the left and rises to the right.Algebra. Graph y=8x-5. y = 8x − 5 y = 8 x - 5. Use the slope-intercept form to find the slope and y-intercept. Tap for more steps... Slope: 8 8. y-intercept: (0,−5) ( 0, - 5) Any line can be graphed using two points. Select two x x values, and plug them into the equation to find the corresponding y y values.Graph of line y = 5 is parallel to X axis. Advertisement Advertisement gopalbisht7644 gopalbisht7644 Answer: The graph of y = 5 is a line parallel to the X - axis . Advertisement Advertisement New questions in Math. √225 is rational or irrational The____of circle intersects at the centre.Pre-Algebra. Graph x=5. x = 5 x = 5. Since x = 5 x = 5 is a vertical line, there is no y-intercept and the slope is undefined. Slope: Undefined. y-intercept: No y-intercept. Find two points on the line. x y 5 0 5 1 x y 5 0 5 1. Graph the line using the slope, y-intercept, and two points.Graph y=3x^2-5. Step 1. Find the properties of the given parabola. Tap for more steps... Step 1.1. Rewrite the equation in vertex form. Tap for more steps... Step 1.1.1. ... The focus of a parabola can be found by adding to the y-coordinate if the parabola opens up or down. Step 1.6.2. Substitute the known values of , , and into the formula and ...The slope is undefined... and where does it cross the Y-Axis? In fact, this is a special case, and we use a different equation, not "y=...", but instead we use "x=... ". Like this: x = 1.5. Every point on the line has x coordinate 1.5, that is why its equation is x = 1.5Graph y = 5x + 5. Linear Equation: One way to easily graph a linear equation is to find the slope and the y-intercept. This process is applicable if the equation is written in the slope-intercept form. Otherwise, we can use other methods such as locating the points of the graph.Graph of y = f(-x) This has the effect of reflecting the graph about the \(y\)-axis. Summary. Next page. Inverse of a logarithmic or exponential function. More guides on this topic.Rewrite in slope-intercept form. Tap for more steps... y = 5 6x y = 5 6 x. Use the slope-intercept form to find the slope and y-intercept. Tap for more steps... Slope: 5 6 5 6. y-intercept: (0,0) ( 0, 0) Any line can be graphed using two points. Select two x x values, and plug them into the equation to find the corresponding y y values.Use the slope-intercept form to find the slope and y-intercept. Tap for more steps... Slope: −2 - 2. y-intercept: (0,5) ( 0, 5) Graph a dashed line, then shade the area below the boundary line since y y is less than −2x+5 - 2 x + 5. y < −2x+5 y < - 2 x + 5. Free math problem solver answers your algebra, geometry, trigonometry, calculus ...Graph x+5y=5. Step 1. Solve for . Tap for more steps... Step 1.1. Subtract from both sides of the equation. Step 1.2. Divide each term in by and simplify. Tap for more steps... Step 1.2.1. ... Graph the line using the slope and the y-intercept, or the points. Slope: y-intercept: Step 6Rewrite in slope-intercept form. Tap for more steps... y = 5 3x+ 4 y = 5 3 x + 4. Use the slope-intercept form to find the slope and y-intercept. Tap for more steps... Slope: 5 3 5 3. y-intercept: (0,4) ( 0, 4) Any line can be graphed using two points. Select two x x values, and plug them into the equation to find the corresponding y y values.Let's graph y = 2 x + 3 . Recall that in the general slope-intercept equation y = m x + b , the slope is given by m and the y -intercept is given by b . Therefore, the slope of y = 2 x + 3 is 2 and the y -intercept is ( 0, 3) . In order to graph a line, we need two points on that line. We already know that ( 0, 3) is on the line.Algebra. Graph y=1/3f (x+5)-3. y = 1 3 f (x + 5) − 3 y = 1 3 f ( x + 5) - 3. Graph. y = 1 3 ⋅(f (x+5))−3 y = 1 3 ⋅ ( f ( x + 5)) - 3. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor.The Free Graphing Tool for Math Teachers. Give your tests, worksheets, and presentations the professional touch. With GraphFree, you can quickly and easily graph almost anything from high school math. Graph circles, ellipses, and hyperbolas along with their asymptotes. Graph piecewise functions, complete with open and closed endpoints.We have to graph the line. Graphing a line if the linear equation of the line is given is easy process. Consider the equation, y = 3/4 x + 5. Here this is in the slope intercept form of the line. Slope = 3/4 and y intercept = 5. y intercept is the point on the line where it touches the Y axis. So one of the point is (0, 5).Explore math with our beautiful, free online graphing calculator. Graph functions, plot points, visualize algebraic equations, add sliders, animate graphs, and more. Untitled Graph. Save Copy. Log InorSign Up. y1: גיל הזכר. 1. y 1 = 0 ≤ x ≤ 1 0 0: x. 2. y2: גיל הנקבה ...The equation provided is y - 5 = 3/2 (x - 2). To plot this line, we first need to convert the equation to slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept. Starting with the given equation: Add 5 to both sides of the equation to get y = 3/2 (x - 2) + 5.Graph y=5/2*sin(x) Step 1. Use the form to find the variables used to find the amplitude, period, phase shift, and vertical shift. Step 2. Find the amplitude . Amplitude: Step 3. Find the period of . ... Step 6.5.2.3. The final answer is . Step 6.6. List the points in a table. Step 7.In this math video lesson I show how to graph y=(5/3)x. The equation in this video is in slope-intercept form, y=mx+b, and is a common way to graph an equat...Trigonometry. Graph y=5tan (x) y = 5tan (x) y = 5 tan ( x) Find the asymptotes. Tap for more steps... Vertical Asymptotes: x = π 2 +πn x = π 2 + π n for any integer n n. No Horizontal Asymptotes. No Oblique Asymptotes. Use the form atan(bx−c)+ d a tan ( b x - c) + d to find the variables used to find the amplitude, period, phase shift ...Explore math with our beautiful, free online graphing calculator. Graph functions, plot points, visualize algebraic equations, add sliders, animate graphs, and more.

Below is an accurate-to-scale graph of \(y = \cos(x)\) showing several cycles with the `fundamental cycle' plotted thicker than the others. The graph of \(y=\cos(x)\) is usually described as `wavelike' -- indeed, many of the applications involving the cosine and sine functions feature modeling wavelike phenomena.Graph y-x=5. Step 1. Add to both sides of the equation. Step 2. Rewrite in slope-intercept form. Tap for more steps... Step 2.1. The slope-intercept form is , where is the slope and is the y-intercept. ... Graph the line using the slope and the y-intercept, or the points. Slope: y-intercept: Step 6Rewrite in slope-intercept form. Tap for more steps... y = 5 2x− 1 y = 5 2 x - 1. Use the slope-intercept form to find the slope and y-intercept. Tap for more steps... Slope: 5 2 5 2. y-intercept: (0,−1) ( 0, - 1) Any line can be graphed using two points. Select two x x values, and plug them into the equation to find the corresponding y y ...To do so, you are going to set x equal to zero. y = -4 (0) + 5. y = 0 + 5. y = 5. The line will cross the y-axis at y = 5 so you will place a dot at coordinates (0,5) on your graph. From the origin (0,0) count 5 units vertically and place a dot. Now, you will identify your slope, which is represented by the number in front of the variable x.Given equation is [tex]y=-\frac{5}{6} x-4[/tex] If we substitute x = 0, then, y = - 4. So, (0, -4) is a point on the line. ... Graph y=−5/6x−4 . Use the line tool ...

Trigonometry. Graph y=5tan (x) y = 5tan (x) y = 5 tan ( x) Find the asymptotes. Tap for more steps... Vertical Asymptotes: x = π 2 +πn x = π 2 + π n for any integer n n. No Horizontal Asymptotes. No Oblique Asymptotes. Use the form atan(bx−c)+ d a tan ( b x - c) + d to find the variables used to find the amplitude, period, phase shift ...Any line can be graphed using two points. Select two x x values, and plug them into the equation to find the corresponding y y values. Tap for more steps... x y −13 0 0 −13 3 x y - 13 0 0 - 13 3. Graph the line using the slope and the y-intercept, or the points. Slope: − 1 3 - 1 3. y-intercept: (0,−13 3) ( 0, - 13 3)So with that out of the way, x gets as large as 25. So let me graph-- we put those points here. So that is 5, 10, 15, 20, and 25. And then let's plot these. So the first one is in blue. When x is 1/25 and y is negative 2-- When x is 1/25 so 1 is there-- 1/25 is going to be really close to there-- Then y is negative 2.…

Reader Q&A - also see RECOMMENDED ARTICLES & FAQs. To graph the functions y = 5^x and y = log_5 (x) on th. Possible cause: Rewrite in slope-intercept form. Tap for more steps... y = − 1 4x+5 y = - 1 4 x +.